The angle of elevation of the top of the building at a distance of 50 m from its foot on a horizontal plane is found to be 60 degree. Find the height of the building
Answers
Answer:
86.6m
Explanation:
AB represents height of the building, BC represents distance of the building from the point of observation.
In the right triangle ABC, the side which is opposite to the angle 60 degree is known as opposite side (AB), the side which is opposite to 90 degree is called hypotenuse side (AC) and the remaining side is called adjacent side (BC).
Now we need to find the length of the side AB.
tanθ = Opposite side/Adjacent side
tan 60° = AB/BC
√3 = AB/50
√3 x 50 = AB
AB = 50√3
Approximate value of √3 is 1.732
AB = 50 (1.732)
AB = 86.6 m
So, the height of the building is 86.6 m.
Answer:
the answer is 86.60 mtr
Explanation:
let x be the height of the building
In Δ ABC
tan 60 = x/BC
√3 = x/50
50√3= x
x = 50 x 1.732
x = 86.60 mtr
so the height of the building is 86.60 mtr.
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