Question

The angle of elevation of the top of the building at a distance of 50 m from its foot on a horizontal plane is found to be 60 degree. Find the height of the building.

Answer 1

ninty ninty ninty ninty

Answer 2

Answer:

ANSWER: 50 √3

Step-by-step explanation

In ΔABC,

Let,  ∠ACB= 60° (Angle of elevetion)

      BC= 50m (Distance from foot)

      AB is the height of the building

Now,    AB/BC = tan60°

            AB/50 = √3

            AB = 50√3 m

hope it helps, please mark me as the brainiest