The angle of elevation of the top of the building from the foot of the tower is 30° and the angle of elevation of the top of the tower from the foot of the building is 45 degree if the tower is 30 metre high find the height of the building
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Answer:
angle of elevation of the top of a building from the foot of a tower =30
0
angle of elevation of the top of a the tower from the foot of the building =60
0
height of tower =60m
det the height of the building be
′
h
′
m
Let the distance the tower and building be
′
b
′
m
In ΔABC
tan30
0
=
b
h
3
1
=
b
h
h=
3
b
=
3
1
−
3
60
m
=
3
60
m
=20m
In ADC
tan60
0
=
b
60m
3
=
b
60m
b=
3
60
m
∴ height of the building =20m
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