Math, asked by suswinsuraj2006, 4 months ago

the angle of elevation of the top of the. building from the foot of the tower is 30°h​

Answers

Answered by Japji21
2

Answer:

Given height of tower CD=50m

Let the height of the building, AB=h

In right angled △BDC,

⇒ tan60

o

=

BD

CD

3

=

BD

50

⇒ BD=

3

50

m

In right angled △ABD,

⇒ tan30

o

=

BD

AB

3

1

=

3

50

h

3

1

=

50

3

h

∴ h=

3

50

=16.66m

∴ The height of the building is 16.66m.

Similar questions