Question

The angle of elevation of the top of the first storey of a building is 30 degree at a point on the ground distance 15 metres frim its foot.How high its second storey will be,if the angle of elevation of the top of the second storey at the same point is 45 degree

Answer 1

Answer:

Step-by-step explanation:

Let DAB be the 2 storeys in the building with 2nd storey at D and 1st storey

at A. B is the foot of the building.

Let C be the point on the ground 15 m away from the buildings foot.

Now, given that angle of elevation of top of first storey is 30°,

tan ∠ACB =  AB/BC

=> tan 30° = AB/15

=> AB = 15/√3

=> AB = 5√3.

Hence the first storey is 5√3 m high.

Angle of elevation of the top of second storey is given as 45°

i.e., ∠DCB = 45°

=> tan 45° = DB/BC

=>1 = DB/15

=>DB = 5m.

Hence the second storey is 15 m high.

Answer 2

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