Question

The angle of elevation of the top of the first storey of a building is 30° at a pt. on the ground at a distance of 15m from it's foot how high is the second storey if there angle of elevation of the top of second storey at the same point is 45°?

Answer 1

Answer:

Step-by-step explanation:

Let DAB be the 2 storeys in the building with 2nd storey at D and 1st storey

at A. B is the foot of the building.

Let C be the point on the ground 15 m away from the buildings foot.

Now, given that angle of elevation of top of first storey is 30°,

tan ∠ACB = AB/BC

=> tan 30° = AB/15

=> AB = 15/√3

=> AB = 5√3.

Hence the first storey is 5√3 m high.

Angle of elevation of the top of second storey is given as 45°

i.e., ∠DCB = 45°

=> tan 45° = DB/BC

=>1 = DB/15

=>DB = 5m.

Hence the second storey is 15 m high

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