Question

the angle of elevation of the top of the hill from foot of the tower is 30 and angle of elevation of tower from the foot of the hill is 60. find the height of the hill

Answer 1

Answer:

Let AB be the tower and CD be the hill. Then, ∠ACB=30

o

,∠CAD=60

o

 and AB=50 m.

Let CD=x m

In right △BAC, we have,

cot30

o

=

AB

AC

​

3

​

=

50

AC

​

AC=50

3

​

 m

In right △ACD, we have,

tan60

o

=

AC

CD

​

3

​

=

50

3

​

x

​

x=50×3=150 m

Therefore, the height of the hill is 150 m.