Question

the angle of elevation of the top of the tower from a point 60 meters from its foot is 30 degrees. find the height of the tower ​

Answer 1

Step-by-step explanation:

The height of the tower is 20 3^1/2 m.

Answer 2

Answer:

The height of the tower is equal to 20√3 meters.

Step-by-step explanation:

Let consider a tower of height AB.

Given that,  ΔABC, ∠B= 90° and angle of elevation i.e. ∠C=30° and BC=60m,

        ∴                  $tan30^{0} =\frac{AB}{BC} \\ \\ \frac{1}{\sqrt3} = \frac{AB}{60} \\ \\ AB= \frac{60\sqrt3}{3}\\ \\ AB=20\sqrt{3}$

Therefore, the height of the tower equals 20√3 meters.