Question

the angle of elevation of the top of the tower from a point on the ground which is 30 meter away from the foot of the tower is 30° find the height of the tower
$....$
​

Answer 1

Answer:

17.320 m

Step-by-step explanation:

Refer the attached figure

AB = Height of tower

BC = 30 m

∠ACB = 30°

InΔABC

Tan \theta=\frac{Perpendicular}{Base}

Tan30^{\circ}=\frac{AB}{BC}

30 \times \frac{1}{\sqrt{3}}=AB

17.320=AB

Hence The height of tower is 17.320 m