Question

the angle of elevation of the top of the tower from a point on the ground which is 30mts asay from tge foot of tower is 30°.find tye height of the tower​​

Answer 1

Answer:

Here's your answer buddy!

Answer 2

Answer:

17.320 m

Step-by-step explanation:

Refer the attached figure

AB = Height of tower

BC = 30 m

∠ACB = 30°

InΔABC

BC = 30 m

∠ACB = 30°

InΔABC

,

tanθ =$\frac{perpendicular}{base}$

tan 30°=AB/BC

30*$\frac{1}{\sqrt{3} }$= AB

17.320 = AB

Hence The height of tower is 17.320 m

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