Question

the angle of elevation of the top of the tower from a point 15m away from the base is 30⁰. Find the height of the tower​

Answer 1

Answer:

so the required answer is 5√3cm

Answer 2

Let the height be p

$tan\:\theta=\frac{perpendicular}{base}=\frac{p}{15}$

$tan\:30=\frac{1}{\sqrt{3}}$

$\frac{1}{ \sqrt{3}}=\frac{p}{15}$

$\implies\:p=\frac{15}{ \sqrt{3}}$

$\implies\:p\:=\frac{15}{ \sqrt{3} }\times \frac{ \sqrt{3} }{ \sqrt{3} }=\frac{ \cancel15 \sqrt{3} }{ \cancel3} =5\sqrt{3}$

So the height of the tower is

$5\sqrt{3} m$