Question

The angle of elevation of the top of the tower from two points P and Q at distances a and b respectively from the base and in the same line with it are complimentary. Prove that the height of the tower is √ab . Pls try to give the answer with figure...... Points are 30 so only relevant answers....

Answer 1

Answer:

Heres Your Answer..

AB is a tower. D and Care two points on the same side of a tower, BD = a and BC = b.

∠ADB and ∠ACB are the complementary angles.

If ∠ADB = x, then ∠ACB = 90 – x

In ∆ADB,

………… (1)

In ∆ABC,

…………....(2)

Multiplying (1) and (2),

(AB)2 = ab

AB = √ab

Height of tower = AB = √ab

Hence proved.

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