The angle of elevation of the top of the tower id 60 degree and the angle of the elevation of the top of the tower from the foot of the hill is 50m find the height of the hill
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Answer:
height=150m
Step-by-step explanation:
Let h be the height of the hill and x m be the distance between the foot of the hill and foot of the tower.
In rt.△ABC,
Cos 60° = x/h
x = h cot 60°........(i)
In rt.△DBC,
cot 30° = x/50
x = 50 cot 30°........(ii)
Equating (i) and (ii)
h cot 60° = 50 cot 30°
h = 50 cot 30°/cot 60°
h = 50 × √3/1√3 = 50 × 3 = 150 m
Therefore the height of the hill is 150 m.
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