Question

The angle of elevation of the top of the tower is 30° from a point.
Height of the tower is 12 m then distance between the point and foot
of the tower is ............​

Answer 1

Answer:

12√3m

Explanation:

let AB be the tower =12m

Let BC be the distance between the point and the foot of the tower

then,

tan30 =AB/BC

1/√ 3 =12/BC

BC=12√3

therefore distance between the point and the foot of the tower is 12√3m