The angle of elevation of the top of the tower when observed from a point distance 90m from the foot of the tower is 60° then find the height of the tower ?
Options:- a)90 b)90/√3 c)90√3 d)100√3
Answers
Answered by
1
Answer:
Ans: c) 90√3 m
Step-by-step explanation:
Let AB be the height of the tower
AB = h
Let BC be the distance between tower and ground
BC = 90 m
Let C be the angle of the ground.
<C = 60°
By Trigonometry,
\: \: \: \: tan \: c = \frac{h}{90}tanc=90h
Tan 60° = h/90
√3 = h/90
h = 90√3 m
The Height of the Tower = 90√3 m
Explanation:
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Answered by
0
Answer:
Ans: c) 90√3 m
Step-by-step explanation:
Let AB be the height of the tower
AB = h
Let BC be the distance between tower and ground
BC = 90 m
Let C be the angle of the ground.
<C = 60°
By Trigonometry,
\: \: \: \: tan \: c = \frac{h}{90}tanc=90h
Tan 60° = h/90
√3 = h/90
h = 90√3 m
The Height of the Tower = 90√3 m
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