Question

The angle of elevation of the top of the tower when observed from a point distance 90m from the foot of the tower is 60° then find the height of the tower ?
Options:- a)90 b)90/√3 c)90√3 d)100√3​

Answer 1

Answer:

Ans: c) 90√3 m

Step-by-step explanation:

Let AB be the height of the tower

AB = h

Let BC be the distance between tower and ground

BC = 90 m

Let C be the angle of the ground.

<C = 60°

By Trigonometry,

\: \: \: \: tan \: c = \frac{h}{90}tanc=90h

Tan 60° = h/90

√3 = h/90

h = 90√3 m

The Height of the Tower = 90√3 m

Answer 2

Answer:

Ans: c) 90√3 m

Step-by-step explanation:

Let AB be the height of the tower

AB = h

Let BC be the distance between tower and ground

BC = 90 m

Let C be the angle of the ground.

<C = 60°

By Trigonometry,

\: \: \: \: tan \: c = \frac{h}{90}tanc=90h

Tan 60° = h/90

√3 = h/90

h = 90√3 m

The Height of the Tower = 90√3 m