the angle of elevation of the top of the verticle tower on a level ground from point at a distance of 9√3m from the foot on the same ground is 60°. find the height of the tower
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Answer:
let h be the height of the tower
therefore, tan60=p/b
root 3=p/9 root 3
root 3 ×9 root 3=p
27=p
p=27
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