Question

the angle of elevation of the top of the water tank from the point on the ground ,which is 50 meter away feom the foot of the water tank .,is 45 degree. Find the height of the tower​

Answer 1

Hey friend,

Here is the solution :-

$here \: the \: angle \: of \: elevation \: is \: {45} \: degree$

$distance \: from \: the \: foot \: of \: \\ the \: tank \: is \: 50 \: metres$

So, we have base = 15 m and we have to find the height

So, tanθ = p/b (here θ = 45°)

$\tan(45) = \frac{p}{50} \\ \\ now \: \tan(45) = 1 \\ \\ 1 = \frac{p}{50} \\ \\ 1 \times 50 = p \\ \\ p = 50 \: metres$

Hence, the height of the water tank is 50 metres.

I hope this will help you....