Math, asked by Anonymous, 7 months ago

the angle of elevation of the top of two towers at a point on the ground and at a equal distance from the base of each tower are 45⁰ and 60⁰. what will be the ratio of thier lengths

Answers

Answered by Mrsekhar

Step-by-step explanation:

Let AB and CD are two towers.

BD=120m=EC, ∠ACE=30

, ∠CBD=24

In right angle △CBD,

tan24

120

CD=120×0.4452

=53.42m

In right angle △ACE,

tan30

120

AE=120×0.5773

=69.28m

AB=AE+EB

=AE+CD [EB=CD]

=69.28+53.42

=122.7m

Height of 1 st

tower is 122.7m and 2 nd

tower is 53.42m.

Hope it helps you

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the angle of elevation of the top of two towers at a point on the ground and at a equal distance from the base of each tower are 45⁰ and 60⁰. what will be the ratio of thier lengths​

Answers

Hope it helps you

Mark me brainliest

the angle of elevation of the top of two towers at a point on the ground and at a equal distance from the base of each tower are 45⁰ and 60⁰. what will be the ratio of thier lengths