the angle of elevation of the top of two towers at a point on the ground and at a equal distance from the base of each tower are 45⁰ and 60⁰. what will be the ratio of thier lengths
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Step-by-step explanation:
Let AB and CD are two towers.
BD=120m=EC, ∠ACE=30
o
, ∠CBD=24
o
.
In right angle △CBD,
tan24
o
=
BD
CD
=
120
CD
CD=120×0.4452
=53.42m
In right angle △ACE,
tan30
o
=
EC
AE
=
120
AE
AE=120×0.5773
=69.28m
AB=AE+EB
=AE+CD [EB=CD]
=69.28+53.42
=122.7m
Height of 1 st
tower is 122.7m and 2 nd
tower is 53.42m.
Hope it helps you
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