Question

the angle of elevation of top of a tower from a point on the ground which is 30 metres away from the foot of the tower is 30° find the height of Tower​

Answer 1

Answer:

Step-by-step explanation:

we know that,

tan 30 = 1/√3

so, 1/√3 = ab/30

⇄ 30 = √3ab

∴ ab = 30/√3

multiplying √3 on numerator and denominator, we get

30√3/3=ab

⇄ 10/√3 = ab

Answer 2

Answer:

the height of the building is 10√3 m

Step-by-step explanation:

let height of building = h

angle of elevation= 30°

base= 30 m

therefore; tan30° = h/30

1/√3 = h/30

h= 30/√3

on rationalising h= 10√3 m