Question

The angle of elevation of top of a tower from a point on the ground , which is 52m away from the foot of the tower is 45°. Find the height of the tower

plz do it fast

Answer 1

Answer:

52 m

Explanation:

let's consider a triangle ABC in which, BC-52 m,

angle ACB- 45', we need to find,AB-?

we know that

angle ACB-P/B

tan45'-AB/52

1-AB/52(tan 45'-1)

AB-52*1

therefore, AB-52m

Hence, found