Question

The angle of elevation of top of a tower is 60° and the angle of elevation of top of tower from the foot of hill is 30° if tow tower is 50m high find the height of hill​

Answer 1

Step-by-step explanation:

Let AB be the tower and CD be the hill. Then, ∠ACB=30

o

,∠CAD=60

o

and AB=50 m.

Let CD=x m

In right △BAC, we have,

cot30

o

=

AB

AC

3

=

50

AC

AC=50

3

m

In right △ACD, we have,

tan60

o

=

AC

CD

3

=

50

3

x

x=50×3=150 m

Therefore, the height of the hill is 150 m.