The angle of elevation of top of a vertical tower from a point on the ground is 60°.from another point 10m vertically above the first its angle of eleveation is 45°.find the height of the tower
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Let the height PQ be x. then, as XY is 40, therefore the height from Q to the point parallel to Y will be x - 40 m.
Now, x/PX = tan 60 = √3
also, (x-40) / PX = tan 45 = 1
solving for PX, we get, PX = (x-40)
substituting in eqn 1, we get, x/x-40 = √3
solving for x, we get x = 40√3 / (√3 - 1) m, which is the required height.
Now, x/PX = tan 60 = √3
also, (x-40) / PX = tan 45 = 1
solving for PX, we get, PX = (x-40)
substituting in eqn 1, we get, x/x-40 = √3
solving for x, we get x = 40√3 / (√3 - 1) m, which is the required height.
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