the angle of elevation of top of the chimney from the top of a tower is 60 degree and the angle of depression of the top of the foot of chimney from the top of the tower is 30 degree if the height of the tower is 40 m find the height of the chimney according to pollution control the minimum height of the smoke emitting Chimney should be hundred metre if the height of the above mentioned in the pollution norms what values discuss this question
Answers
Answer:
take height of the chimney be AB amd height of tower be CD and the horizontal level be CE
Given : the angle of elevation of the top of a chimney from the top of a tower is 60 degree and the angle of depression of the foot of the chimney from the top of the tower is 30 degree. if the height of the tower is 40m
To find : height of the chimney
Solution :
Tower height = 40 m
Let say chimney Height = H m
Chimney height above tower = H - 40 m
Horizontal Distance between tower & chimney = D m
angle of elevation of the top of a chimney from the top of a tower is 60°
=> Tan 60 = (H - 40)/ D
=> √3 = (H - 40)/ D
=> D√3 = H - 40
angle of depression of the foot of the chimney from the top of the tower is 30°
=> Tan 30 = 40/D
=> 1/√3 = 40/D
=> D = 40√3
=> D√3 = 120
H - 40 = 120
=> H = 160
Chimney height = 160 m
120 m above tower height
Meetings the pollution Norms
Meetings the pollution NormsHence obeying the law & environment friendly