Question

the angle of elevation of top of the tower two points p and q at the distance of a and b respectively from the base at its same height line
with it are complementary prove that the height of the tower is root ab

Answer 1

Answer:

• From the above figure you can see and get your answer and verify it.
• In the figure, In

In triangleABP

tanP= AB÷BP

tanP=AB÷a

In triangle ABQ

tanQ=AB÷BQ

tanQ=AB÷b

but from the figure we get that

tanQ=cotP

which implies cotP=AB÷b

cotP ×tanP=1

implies:

(AB÷a) × (AB÷b)=1

AB^2÷ab=1

AB^2=ab

AB=

$\sqrt{ab}$

hence proved as AB is the height of the tower.

Answer 2

Answer:

Check your answer please