Question

The angle of elevation of top of tower from point on ground which is 30m away from foot of tower is 30°. Find height of a tower

Answer 1

Answer:

30√3

Step-by-step explanation:

As it is given that the distance is 30m then BC = 30 and In ∆ABC, angle C = 30 degree.

So,

tan30 = AB upon BC

1 upon √3 = AB upon 30

AB = 30√3

Answer 2

Answer:

17.320 m

Step-by-step explanation:

Refer the attached figure

AB = Height of tower

BC = 30 m

∠ACB = 30°

InΔABC

$Tan \theta=\frac{Perpendicular}{Base}$

$Tan30^{\circ}=\frac{AB}{BC}$

$30 \times \frac{1}{\sqrt{3}} = AB$

17.320 = AB

Hence The height of tower is 17.320 m