Question

The angle of elevation og top of tower a point on ground which is 30m away from the foot of tower is 30 hight of tower is

Answer 1

please mark it brainliest.

Answer 2

Solution :

In ∆ ABC,

tan ∅ = Opposite side / Adjacent side

tan 30° = AB/BC

1/√3 = AB/30

30/√3 = AB

AB = 30/√3

Now, Multiplying numerator and denominator by 3 we get:

AB = 30/√3 × √3/√3

AB = 30√3/3

AB = 10√3

Therefore, the height of the tower is 10√3.