Question

the angle of elevation the top of a tower from a point of the ground which is 30m away from the foot of the tower is 30degree find the height of the tower

Answer 1

Hope it helps you.
If you like then mark it brainliest.

Answer 2

Answer:

In ∆ ABC,

tan ∅ = Opposite side / Adjacent side

tan 30° = AB/BC

1/√3 = AB/30

30/√3 = AB

AB = 30/√3

Now, Multiplying numerator and denominator by 3 we get:

AB = 30/√3 × √3/√3

AB = 30√3/3

AB = 10√3

Therefore,height of the tower is 10√3 m