Question

the angle of elevation to a top of tower from a point at distant 10√3 m from the foot of tower is 60 degree find the height of tower​

Answer 1

Answer:

First make a triangle ABC in which AB is the tower ,BC is the distance of point from foot of the tower , and angle C =60°

After this apply tan 60° =AB/BC

tan60°=Ab/10✓3

and by cross multiplying

AB =10✓3 multiply by ✓3 which is equal to 30metre

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Answer 2

Answer:

15 m

let ab is the height of tower

sin60 =ab /10×1.732

1.732/2=ab/10×1.732

ab =15m

where

1.732=the square root value of three

sorry I can't write square root three mathematically so I have to put the value of root three