Question

the angle of elevation top of building is 150m high from the point of ground is 45 degree find distance of the point from the foot of building​

Answer 1

Answer:

let the height of building of 150m is AB

the angle of elevation is 45 from point C

and angle B = 90

now , in right angled triangle ABC

AB/BC = tan45

150/BC = 1. ( tan 45 = 1)

150 = Bc

so distance of building from given point is 150m

Step-by-step explanation: