The angle of elevations of the top a tower from a point on the ground which is 30m away from
the foot of tower is 30 find the height of tower.
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Answered by
1
Answer:
17.320 m
Step-by-step explanation:
Refer the attached figure
AB = Height of tower
BC = 30 m
∠ACB = 30°
InΔABC
Tan \theta=\frac{Perpendicular}{Base}Tanθ=BasePerpendicular
Tan30^{\circ}=\frac{AB}{BC}Tan30∘=BCAB
30 \times \frac{1}{\sqrt{3}}=AB30×31=AB
17.320=AB17.320=AB
Answered by
0
Answer:
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