The angle of evelation of the top building from a point of the ground which 10m away from the building is found to be 45° find, the height of the building
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Answer:
sorry not sure it's correct or not
In ΔBAP
tan30
o
=
AP
AB
⇒
3
1
=
x
10
x=10
3
m
Distance of building
Now,
In ΔPAD
tan45
o
=
AP
AD
1=
AP
AD
⇒x=AD=DB+BA
⇒10
3
=h+10
h=10
3
−10
=10(
3
−1)
h=10(1.732−1)
h=7.32m
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