Question

the angle of incidence is 45 , the refractive index of 1st medium is 1, the refractive index of 2nd medium is
$1 \div \sqrt{2}$
then what is the angle of refraction?
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Answer 1

Answer:

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Answer 2

Answer:

$r=90^0$

Explanation:

Using snell's law:-

$\boxed{\mu_1sin(i)=\mu_2sin(r)}$

Where $\mu_1 :$ refractive index of $1^{st}$ medium

           $\mu_2:$ refractive index of $2^{nd}$ medium

On putting in the values, we get :

$=> (1)sin45^0=(\frac{1}{\sqrt{2}})sinr \\\\=>sin(r)=1\\\\=>\boxed{r=90^0}$

Hope this answer helped you :)