Question

The angle of inclination of the object from the top of a straight building at 50√3 m above the flat ground is 60 °. Then the distance from the base of the building to the object ... *​

Answer 1

The angle of inclination of the object from the top of a straight building is 60⁰.

• Height of the building = 50√3 m

Let the Distance b/w Building base and Object be x.

→ tan ∅ = Perpendicular/Base

→ tan 60⁰ = 50√3/x

→ √3 = 50√3/x

→ x = 50√3/√3

→ x = 50

Hence,

It is Proved that the Distance between the base of the building and the Object will be 50 metres.