Question

The angle of projection is 30°. The ratio of the horizontal range and the maximum height?

Answer 1

Answer: 4√3:1

Explanation:

The horizontal range of a projectile is given by

$R=\frac{u^{2}sin2A }{g}$

where symbols have their usual meanings, and A is the angle of projection.

The maximum height of a projectile is given by

$H(max)=\frac{u^{2}sin^{2}A }{2g}$

For A=30°,

$R:H(max) = \frac{u^{2}sin60}{g} :\frac{u^{2}sin^{2}30}{2g}$

(can't enter the degree sign in the angles, apologies.)

Solving by substituting and cancelling out, we get

$R:H(max)=4\sqrt{3}:1$