Question

The angle of projection of a projectile is 30°, Then find the ration between its range of projectile and
maximum height?

Urgent help needed please ​

Answer 1

Answer:

The angle of projection of a projectile is 30°, Then find the ration between its range of projectile and

maximum height?

Urgent help needed please

Answer 2

Answer:

4√3

Explanation:

Range of the projectile = $\frac{u^{2} sin(2x) }{g}$

Hence Range = $\frac{\sqrt{3} u^{2} }{2g} }$

Maximum Height of the projectile = $\frac{u^{2} sin^{2}( x) }{2g}$

Hence Maximum Height = $\frac{u^{2} }{8g}$

Ratio of Range and Height = $\frac{\sqrt{3} u^{2} }{2g} }$÷ $\frac{u^{2} }{8g}$ = $\frac{\sqrt{3} u^{2} }{2g} }$ × $\frac{8g }{u^{2}}$ = 4√3

Hoping that I have not made any mistakes, You're welcome.

Hope you have found my answer useful. If my answer deserves a brainliest, do mark it.

GeniusH