the angle of projection of a projectile which is projected with certain velocity from ground is pi by 8 with horizontal and its horizontal range is R. The angle with the horizontal for another projectile having same range R and speed is
1) 3pi/8
2)pi/4
3)pi/3
4)pi/6
kindly tell me how to solve this question
Answers
Answered by
78
The correct answer to this question is option 1) 3π/8.
Given: The angle of projection of a projectile which is projected with a certain velocity from the ground is π/8 with horizontal and its horizontal range is R.
To Find: The angle with the horizontal for another projectile having the same range R and speed.
Solution:
We know that,
For any angle θ, another angle having the same speed would have the same projectile range will be 90° - θ.
Here,
θ = π/8
So,
90° - θ = π/2 - π/8 .........(180° = π, ∴ 90° = π/2)
= 3π/8
Hence, the angle with the horizontal for another projectile having the same range R and speed is 3π/8.
Answered by
9
Answer:
hope this helps
Explanation:
fact= Complementary anglles have same ranges
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