Question

the angle of projection of a projectile with a horizontal direction for which the maximum height attained by the projectile is equal to the range of the projectile is?
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Answer 1

Question ⤵

the angle of projection of a projectile with a horizontal direction for which the maximum height attained by the projectile is equal to the range of the projectile is?

Answer ⤵

$r = \frac{ {u}^{2} sin \: 20}{g} \\ h = \frac{ {u}^{2} \: {sin}^{2} 0}{2g} \\ \\ \frac{ {u}^{2} \: sin \: 20}{g} = \frac{ {u}^{2} \: {sin}^{2} \: 0}{2g} \\ 2 \: sin \: 0 \: cos \: 0 = \frac{ {sin}^{2} \: 0}{2} \\ u \: cos \: 0 = sin \: 0 \\ tan \: 0 = 4 \\ 0 = tan {}^{ - 1} \: 4$