Question

The angle of projection of projectile for which its max height is equal to one fourth of its horizontal range is
A:30°
B:45°
C:60°
D:75°

Answer 1

Answer:

B.45 degrees

Explanation:

equating formula of hmax and range

(1u^(2)sin2theta)/(4g)=(1u^(2)sin^(2)theta)/(2g)

simply the equation

then sin2thetha can be expanded as 2sinthetacostheta

2sinthetacostheta=2sin^2theta

cancelling we get

costheta/sintheta =1

cot theta=1

cot inverse of 1 is 45

so the angle of projection is 45 degrees

Answer 2

Answer:

answer is 45 degree

hope you will understand