the angle of quadrilateral are X degree in (2 X + 13) (3X + 10) (x-6) then find the value of x.
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Answered by
6
X+ (2X +13)+(3X+10)+(X-6)=360°(Sum of all the angles of a quad.)
=7X +17=360°
=7X=360°-17
=7X=343
X=343/7
=49
Hope this answer will help you...
=7X +17=360°
=7X=360°-17
=7X=343
X=343/7
=49
Hope this answer will help you...
Answered by
0
sum of angles of a quad = 360
=> x+(2x+13)+(3x+10)+(x-6)=360
=> 7x+17=360
=> 7x=343
=> x=49
I hope this will help you
if not then comment me
=> x+(2x+13)+(3x+10)+(x-6)=360
=> 7x+17=360
=> 7x=343
=> x=49
I hope this will help you
if not then comment me
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