The angle of refraction for a ray of light in a plastic block with a refractive index (1.4) is 25degree. Calculate the angle of incidence.
a. 84degree
b. 40degree
c. 36degree
d. 17degree
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Refractive index of a plastic block is 1.4 and angle of refraction is 25°.
We are asked to find angle of incidence.
Assuming that light is coming from air. We know that refractive index of air is 1.
This question is based on the concept of snell's law. Mathematical expression of snell's law is given by;
- n₁ sin i = n₂ sin r
Where n₁ and n₂ denotes refractive indices of two different media, i denotes angle of incidence and r denotes angle of refraction
By substituting the given values;
=> n₁ × sin i = n₂ × sin r
=> 1 × sin i = 1.4 × sin 25°
=> sin i = 1.4 × 0.42
=> i = sin‾¹ (0.588)
=> i = 36°
Answered by
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Answer:
Refractive index of a plastic block is 1.4 and angle of refraction is 25°.
We are asked to find angle of incidence.
Assuming that light is coming from air. We know that refractive index of air is 1.
This question is based on the concept of snell's law. Mathematical expression of snell's law is given by;
n₁ sin i = n₂ sin r
Where n₁ and n₂ denotes refractive indices of two different media, i denotes angle of incidence and r denotes angle of refraction..
By substituting the given values;
=> n₁ × sin i = n₂ × sin r
=> 1 × sin i = 1.4 × sin 25°
=> sin i = 1.4 × 0.42
=> i = sin‾¹ (0.588)
=> i = 36°
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