The angle of revolution of the top of atower from two points at a dist of 4cm and 9m from the base of the tower and in the same straight line the tower is 6m.
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In angle ABC, We Can
A/B=tanQ
H/9=tanQ
In angle, we have
A/B=tan (90'-Q) H/4=cotQ
From(1)and(2),we haveH/9*H1/4=tan*cotQ
H2=36 = h=6
This is answer ur question●︿●●︿●●_●●_●●_●●_●●_●
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