Question

the angle of the quadrilateral are X degree, ( x- 10) degree, ( x+30) degree and (2x) degree the smallest angle is equal to :-
(a) 68 degree
(b) 52 degree
(c)58 degree
(d) 47 degree

Answer 1

Answer:

58 degree

Step-by-step explanation:

sum of the interior angles of a quadrilateral = 360 degree

angle A = x

angle B = x-10

angle C = x+30

angle D = 2x

this means : x+(x-10)+(x+30)+(2x) = 360 degree

                    3x+2x+20 = 360 degree

                     5x = 340 degree

                     x = 68 degree

angle A= x = 68 degree

angle B= x-10= 58 degree

angle C= x+30=98 degree

angle D= 2x= 136 degree

clearly angle B is the smallest

therefore smallest angle is 58 degree

Answer 2

Step-by-step explanation:

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