the angle of the quadrilateral are X degree, ( x- 10) degree, ( x+30) degree and (2x) degree the smallest angle is equal to :-
(a) 68 degree
(b) 52 degree
(c)58 degree
(d) 47 degree
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Answered by
15
Answer:
58 degree
Step-by-step explanation:
sum of the interior angles of a quadrilateral = 360 degree
angle A = x
angle B = x-10
angle C = x+30
angle D = 2x
this means : x+(x-10)+(x+30)+(2x) = 360 degree
3x+2x+20 = 360 degree
5x = 340 degree
x = 68 degree
angle A= x = 68 degree
angle B= x-10= 58 degree
angle C= x+30=98 degree
angle D= 2x= 136 degree
clearly angle B is the smallest
therefore smallest angle is 58 degree
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