Question

The angle of the quadrilateral PQRS are 2x degree ,(3x + 10 ) degree (4x +15 ) degree and (x-5) degree find the measure each of the quadrilateral​

Answer 1

Answer:

sum of the angles in a quadrilateral = 360

x + ( x - 10 ) + ( x + 30 ) + 2x = 360

x + x + x + 2x -10 +30 = 360

5x + 20 = 360 

5x = 360 - 20

5x = 340

x = 340 / 5

x = 68

first angle = x = 68°

second angle = x - 10 = 68 - 10 = 58°

third angle = x + 30 = 68 + 30 = 98°

fourth angle = 2x = 2 × 68 = 136°

Answer 2

Answer:

$\sf29°$

$\sf151°$

$\sf112°$

$\sf68°$

Step-by-step explanation:

As we all know a quadrilateral is always equals to 360°

so,

(2x)+(3x+10)+(4x+15)+(x-5)=360°

10x +10 +15-5=360°

10x = 360-20

x = 340/10

»»$\texttt{x}$= $\sf34°$

so the value of x is 34°

Other Angles

(x-5) = 34-5 = 29°

(4x+15) = 136+15 = 151

(3x+10) = 102 + 10 = 112

2x = 68

Brainliest plz