Question

the angle ovulation on the top of the table from this point on the ground which is 15 m away from the foot of the tower,is 60 degree .The height of the tower is​

Answer 1

Answer:

Step-by-step explanation:

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Height of building  L = 30 m

Angle from top of building   theta = 30 deg

Angle from top of tank     A = 45 deg

Let the height of tank be x

tan theta = L/ B

tan 30 = 30 / B

B = 30 m

Now

tan A = x + L / B

x + L = tan 45 * 20

x  =  30 ( root 3 - 1)

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