The angle substended by vector A=4i+3J+12K with the x axis is
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Answer:72.1 degree
Explanation:
The vector on the x axis is U(x) = (1, 0, 0)
Vector A = (4, 3, 12)
Use DOT product and inverse Cosine to find the angle.
A dot U =IIAII IIUII cos(angle between them)
Angle between them = cos^-1 { (A dot U) / (IIAII IIUII) }
IIAII = 13
IIUII = 1
A dot U = 4
Angle = cos^-1 (4/13) = 72.1 degree
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