Question

the angle subtended by chords AC and CB at the centre O measure 90° and 116° respectively. find the measure of angle BCA​

Answer 1

Answer:

Step-by-step explanation:

OA=OB=OC=radius

In △OBC

Since OB=OC

∠OBC=∠OCB

∠BOC=155

∠OBC+∠OCB+∠BOC=180

2∠OCB=180−155

∠OCB=12.5

Similarly in △OAC

2∠OCA=180−55

∠OCA=62.5

2∠OCB=180−155

∠OCB=12.5

SCB = 2∠OCB=180−155

∠OCB=12.5

OCB + 2∠OCB=180−155

∠OCB=12.5°

OCA=12.5+62.5=75°

Answer 2

Answer:

hope it is helpful for you