Question

the angle subtended by two Flagstaffs, if height 10m and 15m respectively at a certain point P, on the ground between them, are complementary. if the distance of P from the foot of the Flagstaffs of height 10m is 5m, find the distance between the two Flagstaffs.​

Answer 1

Answer:

Let RS be pole of height 10 m and PT be pole of height 15m.

ST is the distance between their feet i.e. 12m.

∴RQ=ST=12 m         

And, RS=QT=10m              ....[∵□RQTS is a rectangle]

Now, in △PQR,

By Pythagoras theorem,

PR2=PQ2+QR2

∴PR2=52+122=25+144

PR=13 m.

Hence, the distance between their tops is 13m.

Answer 2

Conclusion

Pythagoras Theorem

Given the Pythagorean Theorem, $a^2 + b^2 = c^2$ , for an acute triangle, $c^2 < a^2+b^2$, where c is the opposing side of the acute angle. $c^2 = a^2 + b$for a right triangle, where c is the side of the 90-degree angle. $c^2 > a^2 + b^2$ for an obtuse triangle, where c is the side opposite the obtuse angle.

Main content

Let RS be pole of height 10 m and PT be pole of height 15m.

ST is the distance between their feet i.e. 12m.

∴RQ=ST=12 m        

And, RS=QT=10m              

[∵□RQTS is a rectangle]

Now, in △PQR,

By Pythagoras theorem,

PR2=PQ2+QR2

∴PR2=52+122=25+144

PR=13 m.

Hence, the distance between their tops is 13m

To learn more about Pythagorean Theorem

https://brainly.in/question/48490459

#SPJ2