Math, asked by batismarkalexi6988, 1 year ago

The angle subtended by vector a =4i^+3j^+12k^ with x-axis is

Answers

Answered by amitnrw
13

Answer:

72.1°

Step-by-step explanation:

The angle subtended by vector a =4i^+3j^+12k^ with x-axis is

i  represent x axis  & Let say α is the  angle subtended by vector a =4i^+3j^+12k^ with x-axis

Cos α =  4/√(4² + 3² + 12²)

=> Cos α =  4/ √(16 + 9 + 144)

=>  Cos α =  4/ √169

=> Cos α = 4/13

=> α = Cos⁻¹(4/13)

=> α = 72.1 °

The angle subtended by vector a =4i^+3j^+12k^ with x-axis is 72.1°

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