The angle subtended by vector a =4i^+3j^+12k^ with x-axis is
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Answer:
72.1°
Step-by-step explanation:
The angle subtended by vector a =4i^+3j^+12k^ with x-axis is
i represent x axis & Let say α is the angle subtended by vector a =4i^+3j^+12k^ with x-axis
Cos α = 4/√(4² + 3² + 12²)
=> Cos α = 4/ √(16 + 9 + 144)
=> Cos α = 4/ √169
=> Cos α = 4/13
=> α = Cos⁻¹(4/13)
=> α = 72.1 °
The angle subtended by vector a =4i^+3j^+12k^ with x-axis is 72.1°
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