Question

The angle that √3i -j vector makes with the positive x-axis is​

Answer 1

Answer:

Magnitude of √3i -j = 2

Vector becomes [ (√3/2) i, 1/2 j ] ( lies in 1st quadrant )

cos theta = √3/2 and sin theta = 1/2

Angle (theta ) with positive X - axis = 30° or π/6